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Answered By: Sara Stambaugh, Digital Services Librarian
Last Updated: May 27, 2016     Views: 125

Bicycles (b) and Tricycles (t)

Solve for b and t:

2b + 3t = 23

 

In this particular instance, the numbers will become fractions of bikes and trikes (there is no way to get whole number answers with an exact ratio of 2:1) But no one said anything about unicycles, so my guess is 6 bikes, 3 trikes, and 2 unicycles (u).

2b + 3t + 1u = 23

2(6) + 3(3) = 12 + 9 = 21

21 + 1(2) = 23

 

------ OR ------

 

If the ratio of bikes to trikes doesn't have to be exactly 2:1 (where you have at least twice as many bikes than trikes) then you could have 7 bikes and 3 trikes. which would look like:


2(7) + 3(3) = 14 + 9 = 23