Chat with the Rasmussen Library
Chat Hours
Monday-Thursday |
12pm-8pm CT |
Friday | Offline |
Saturday | Offline |
Sunday | 4pm-8pm CT |
Submit a Question
Answered By: Sara Stambaugh, Digital Services Librarian Last Updated: May 27, 2016 Views: 163
Answered By: Sara Stambaugh, Digital Services Librarian
Last Updated: May 27, 2016 Views: 163
Bicycles (b) and Tricycles (t)
Solve for b and t:
2b + 3t = 23
In this particular instance, the numbers will become fractions of bikes and trikes (there is no way to get whole number answers with an exact ratio of 2:1) But no one said anything about unicycles, so my guess is 6 bikes, 3 trikes, and 2 unicycles (u).
2b + 3t + 1u = 23
2(6) + 3(3) = 12 + 9 = 21
21 + 1(2) = 23
------ OR ------
If the ratio of bikes to trikes doesn't have to be exactly 2:1 (where you have at least twice as many bikes than trikes) then you could have 7 bikes and 3 trikes. which would look like:
2(7) + 3(3) = 14 + 9 = 23
Was this helpful? 1 0